Question
Shyam walks 6 m towards East, then turns right and walks 9 m. Again, he turns to his left and walks 6 m. At what distance is he now from his original point?
Answer: Option A
Answer: (a)
According to the question, the direction diagram is as follows. O is the mid - point of BC and
AD OB = OC = $9/2$ = 4.5 m
OA = $√{(AB)^2 + (OB)^2}= √{(6)^2+ (4.5)^2}$
= $√{(36 + 20.25)} = √{(56.25)}$ = 7.5 m
OD = OA = 7.5
Therefore, Required distance, AD = AO + OD = 7.5 + 7.5 = 15 m.
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Answer: (a)
According to the question, the direction diagram is as follows. O is the mid - point of BC and
AD OB = OC = $9/2$ = 4.5 m
OA = $√{(AB)^2 + (OB)^2}= √{(6)^2+ (4.5)^2}$
= $√{(36 + 20.25)} = √{(56.25)}$ = 7.5 m
OD = OA = 7.5
Therefore, Required distance, AD = AO + OD = 7.5 + 7.5 = 15 m.
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