Question
Parul and Vijay throw 3 dice in a single throw. It is known that Parul throws a total of 16. Find Vijay’s probability of getting a higher value.
Answer: Option C
:
C
The maximum total possible = 18
There are two options for Vijay
1) A+B+C=17 Possibilities = 6,6,5
Number of combinations = 3!2! =3
2) A+B+C=18Possibilities = 6,6,6
Number of combinations = 1
Required Probability= 4216 = 152.
Option (c)
Was this answer helpful ?
:
C
The maximum total possible = 18
There are two options for Vijay
1) A+B+C=17 Possibilities = 6,6,5
Number of combinations = 3!2! =3
2) A+B+C=18Possibilities = 6,6,6
Number of combinations = 1
Required Probability= 4216 = 152.
Option (c)
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution