Question
Determine the no. of terms in the expansion of (a+b+c+d)5 and (1+a+a2+a3)5
Answer: Option A
:
A
No. of terms in expansion of (a+b+c+d)5 = Number of solution of (a + b + c + d) = 5, 8C3 = 56
No. of terms in expansion of (1+a+a2+a3)5=(5×3)+1=16
Hence option (a)
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A
No. of terms in expansion of (a+b+c+d)5 = Number of solution of (a + b + c + d) = 5, 8C3 = 56
No. of terms in expansion of (1+a+a2+a3)5=(5×3)+1=16
Hence option (a)
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