Exams > Cat > Quantitaitve Aptitude
MODERN MATHS MCQs
Total Questions : 95
| Page 1 of 10 pages
Answer: Option A. -> 55
:
A
Use the concept of grouping, for a three digit number ABC
A+B+C = 10, A >1
It changes to A + B + C = 9
Number of possible solutions = 11C2=55
:
A
Use the concept of grouping, for a three digit number ABC
A+B+C = 10, A >1
It changes to A + B + C = 9
Number of possible solutions = 11C2=55
Answer: Option B. -> 6C2
:
B
This is a question based on S‘aD with a varying lower limit.
Take out 1+2+3=6 from the RHS. Equation changes to
A+B+C = 4. Answer will the arrangement of 4 zeroes and 2 ones = 6C2
:
B
This is a question based on S‘aD with a varying lower limit.
Take out 1+2+3=6 from the RHS. Equation changes to
A+B+C = 4. Answer will the arrangement of 4 zeroes and 2 ones = 6C2
:
If the first digit and last digit of the four digit number needs to be even, then we have to choose numbers out of 2, 6 and 8
The first digit can be chosen in 3 ways and the last digit in 2 ways = 3×2=6 ways
The remaining two digits can be chosen and arranged among the remaining 4 digits in 4P2 ways = 12 ways
Total number of ways = 6×12=72 ways
Answer: Option B. -> 10
:
B
Let’s number the baskets as A,B,C and D
With the first constraint, 2 of the balls are going to basket 2(B), hence we have 5-2=3 balls left to distribute among the remaining baskets.
A+C+D = 3
Number of distributions possible = 5C2 = 10
:
B
Let’s number the baskets as A,B,C and D
With the first constraint, 2 of the balls are going to basket 2(B), hence we have 5-2=3 balls left to distribute among the remaining baskets.
A+C+D = 3
Number of distributions possible = 5C2 = 10
Answer: Option D. -> 69760
:
D
Total number of 5 digit telephone numbers which can be formed using digits 0,1,2…9 is 105
Number of 5 digit numbers having not even a single digit repeated is 10P5 = 30240
Required number of telephone numbers = 105 -30240 = 69760
:
D
Total number of 5 digit telephone numbers which can be formed using digits 0,1,2…9 is 105
Number of 5 digit numbers having not even a single digit repeated is 10P5 = 30240
Required number of telephone numbers = 105 -30240 = 69760
Question 6. Arpit and Rita will play one game of Rock, Paper, Scissors. In this game, each will select and show a hand sign for one of the three items. Rock beats Scissors, Scissors beat Paper, and Paper beats Rock. Assuming that both Arpit and Rita have an equal chance of choosing any one of the hand signs, what is the probability that Arpit will win?
Answer: Option D. -> 13
:
D
No matter what sign Arpit throws, there is one sign Rita could throw that would beat it, one that would tie, and one that would lose. Rita is equally likely to throw any one of the three signs. Therefore, the Probability that Arpit will win is13
Probability that Rita will win =13
Probability of a tie =13.
Probability that Arpit will win =13
The correct answer is (d).
:
D
No matter what sign Arpit throws, there is one sign Rita could throw that would beat it, one that would tie, and one that would lose. Rita is equally likely to throw any one of the three signs. Therefore, the Probability that Arpit will win is13
Probability that Rita will win =13
Probability of a tie =13.
Probability that Arpit will win =13
The correct answer is (d).
Answer: Option C. -> 0.19
:
C
Probability of a success= 0.3
Probability of a failure= 0.7
Required Probability = 0.3 × 0.3 × 0.7 ×3C1= 0.189
:
C
Probability of a success= 0.3
Probability of a failure= 0.7
Required Probability = 0.3 × 0.3 × 0.7 ×3C1= 0.189
Answer: Option D. -> 91216
:
D
The probability of getting no six is (56)3= 125216
Hence the probability of getting at least one six is 1- 125216 =91216
:
D
The probability of getting no six is (56)3= 125216
Hence the probability of getting at least one six is 1- 125216 =91216
Answer: Option B. -> 5 : 37
:
B
Probability of all three balls being blue = 5C39C3 = 552
Odds in favour of being blue =5(42−5)= 5 : 37
:
B
Probability of all three balls being blue = 5C39C3 = 552
Odds in favour of being blue =5(42−5)= 5 : 37
Answer: Option D. -> 0.4
:
D
If A is selected, then two more students need to be selected. This can be done in 5C2ways= 10
If C is also selected, only one more out of the remaining 4 needs to be selected.
That can be done in 4 ways.
Thus, Probability =410= 0.4
:
D
If A is selected, then two more students need to be selected. This can be done in 5C2ways= 10
If C is also selected, only one more out of the remaining 4 needs to be selected.
That can be done in 4 ways.
Thus, Probability =410= 0.4
Latest Videos
Latest Test Papers
Login With Google
Old way of Login
Login With Email