Question
One root of the following given equation 2x5−14x4+31x3−64x2+19x+130=0 is
Answer: Option C
:
C
We can solve this problem using options given -
On putting x = 5, we get
2(5)5−14(5)4+31(5)3−64(5)2+19(5)+130=0
Hence x = 5 satisfies the given equation.
Thus 5 is a root of the equation.
Other options will not satisfy the given equation so the answer is x = 5.
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:
C
We can solve this problem using options given -
On putting x = 5, we get
2(5)5−14(5)4+31(5)3−64(5)2+19(5)+130=0
Hence x = 5 satisfies the given equation.
Thus 5 is a root of the equation.
Other options will not satisfy the given equation so the answer is x = 5.
Was this answer helpful ?
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