Question
If the equation 9x2+6kx+4=0 has equal roots, then find the value of k =
Answer: Option D
:
D
Given, the roots of quadratic equation 9x2+6kx+4=0are real and equal.
Discriminant,Δ=b2−4acΔ=36k2–4(4)(9)=36k2–4(36)
The roots of quadratic equation are real and equal thenΔ=036k2–4(36)=0k2−4=0k2=4k=√4∴k=±2
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:
D
Given, the roots of quadratic equation 9x2+6kx+4=0are real and equal.
Discriminant,Δ=b2−4acΔ=36k2–4(4)(9)=36k2–4(36)
The roots of quadratic equation are real and equal thenΔ=036k2–4(36)=0k2−4=0k2=4k=√4∴k=±2
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