Question
If α and β are the roots of the equation 4x2+3x+7=0, then 1α+1β=
Answer: Option A
:
A
Given equation 4x2+3x+7=0, ∴
α+β=−34andαβ=74
Now 1α+1β=α+βαβ=−3474=−34×47=−37
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:
A
Given equation 4x2+3x+7=0, ∴
α+β=−34andαβ=74
Now 1α+1β=α+βαβ=−3474=−34×47=−37
Was this answer helpful ?
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