Question
N=23×32×53×10. If P is a natural number, then how many factors of N are of the form 2P+1?
Answer: Option A
:
A
N=24×32×54. Ultimately, we need to find out the number of odd factors of N except 1. Number of odd factors (including 1) =(2+1)×(4+1)=3×5=15.
Answer- (15−1)=14.
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:
A
N=24×32×54. Ultimately, we need to find out the number of odd factors of N except 1. Number of odd factors (including 1) =(2+1)×(4+1)=3×5=15.
Answer- (15−1)=14.
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