Find the remainder when 9 400 + 9 401 + 9 402 . . . . . . . 9 410 is divided by 6? Options: A . &nbsp0 B . &nbsp1 C . &nbsp3 D . &nbsp2

Answer: Option C : C Any power of 9 when divided by 6, gives a remainder 3. hence answer = 11 × 3 6 ((As there are 11 terms)= 33 6 = Remainder = 3

Find the remainder when 9400+9401+9402.......9410 is divided by 6?

Question

Find the remainder when

9^{400} + 9^{401} + 9^{402} . . . . . . . 9^{410}

is divided by 6?

Options:

A . 0

B . 1

C . 3

D . 2

Answer: Option C
:
C
Any power of 9 when divided by 6, gives a remainder 3. hence answer

= \frac{11 \times 3}{6}

((As there are

11

terms)=

\frac{33}{6}

= Remainder

= 3

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