Question
N=(323232.......50 digits)9. ie in base 9. Find the remainder when N is divided by 8?
Answer: Option D
:
D
In base 9, divisibility check for 8 is sum of the digits(digit sum) =Digit sum of N=(25∗3+25∗2)9=
First convert the numbers to base 10
25 in base 10=23, Thus the question changes to (23∗3+23∗2)10=11510
Converting it back to base 9 = 137, Now sum of digits in base 9=1+3+7=(4+7)9=12⇒1+28∣R=3
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:
D
In base 9, divisibility check for 8 is sum of the digits(digit sum) =Digit sum of N=(25∗3+25∗2)9=
First convert the numbers to base 10
25 in base 10=23, Thus the question changes to (23∗3+23∗2)10=11510
Converting it back to base 9 = 137, Now sum of digits in base 9=1+3+7=(4+7)9=12⇒1+28∣R=3
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