Question
In a triangle ABC, 2 sides AB and AC are of length 5 units each. If a perpendicular of length 3 units is dropped from A to BC, then what is the length of the radius of the circle that can be inscribed in the triangle?
Answer: Option B
:
B
Option (b)
3 sides ofthe triangle along with the perpendicularforms 2right angled triangles. The 3rd side(base of triangle) is hence √(52−32) + √(52−32) = 8.
Area of the triangle = 12.3.8 = rs = (a + b + c) r2, where s is the semiperimeter and r is the inradius of the triangle. Solving r = 2418 = 1.33
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:
B
Option (b)
3 sides ofthe triangle along with the perpendicularforms 2right angled triangles. The 3rd side(base of triangle) is hence √(52−32) + √(52−32) = 8.
Area of the triangle = 12.3.8 = rs = (a + b + c) r2, where s is the semiperimeter and r is the inradius of the triangle. Solving r = 2418 = 1.33
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