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InΔABCandΔEDC,AC=CE(given)∠BAC=∠DEC(since AB||DE and AE is a transversal, so they are alternate angles)∠ACB=∠ECD(vertically opposite angles)∴ΔABC≅ΔEDC(A.S.A. congruence criteria)∴AB=DE(sides of congruent triangles)∴x+10=2x−5⇒x=15units
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InΔABCandΔEDC,AC=CE(given)∠BAC=∠DEC(since AB||DE and AE is a transversal, so they are alternate angles)∠ACB=∠ECD(vertically opposite angles)∴ΔABC≅ΔEDC(A.S.A. congruence criteria)∴AB=DE(sides of congruent triangles)∴x+10=2x−5⇒x=15units
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