Question
In how many different ways can six players be arranged in a line such that two of them, Asim and Raheem are never together?
Answer: Option D
1. AS THERE ARE SIX PLAYERS, SO TOTAL WAYS IN WHICH THEY CAN BE ARRANGED = 6!WAYS =720.
A NUMBER OF WAYS IN WHICH ASIM AND RAHEEM ARE TOGETHER = 5!X2 = 240.
THEREFORE, NUMBER OF WAYS WHEN THEY DON’T REMAIN TOGETHER = 720 -240 =480.
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1. AS THERE ARE SIX PLAYERS, SO TOTAL WAYS IN WHICH THEY CAN BE ARRANGED = 6!WAYS =720.
A NUMBER OF WAYS IN WHICH ASIM AND RAHEEM ARE TOGETHER = 5!X2 = 240.
THEREFORE, NUMBER OF WAYS WHEN THEY DON’T REMAIN TOGETHER = 720 -240 =480.
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