Question
In ΔABC, the line parallel to BC intersect AB & AC at P & Q respectively. If AB : AP = 5 : 3, then AQ : QC is:
Answer: Option A
$$\eqalign{
& \frac{{AP}}{{PB}} = \frac{{AQ}}{{QC}} \cr
& \frac{{AQ}}{{QC}} = \frac{3}{2} \cr
& AQ:QC = 3:2 \cr} $$
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$$\eqalign{
& \frac{{AP}}{{PB}} = \frac{{AQ}}{{QC}} \cr
& \frac{{AQ}}{{QC}} = \frac{3}{2} \cr
& AQ:QC = 3:2 \cr} $$
Was this answer helpful ?
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