In ΔABC, AB=BC=6cm. If a circle is drawn with center at B and radius 2 cm whic

Question

Δ A B C, A B = B C = 6 c m

. If a circle is drawn with center at B and radius 2 cm which intersects AB and BC at E and D, then

Δ A B C \sim Δ E B D

Options:

A . True

B . False

C . MB = 5 cm

D . AC = 5 cm

Answer: Option A
:
A

Δ A B C a n d Δ E B D

\frac{B E}{B A} = \frac{B D}{B C} = \frac{2}{6} = \frac{1}{3} a n d ∠ D B E = ∠ A B C

.
By SAS similarity,

Δ A B C

and

Δ E B D

are similar.

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