Question
△ABC is such thatAB=3 cm,BC=2 cm and CA=2.5 cm. △DEF is similar to △ABC. If EF=4 cm, then the perimeter of △DEF is ____.
Answer: Option B
:
B
ABDE =ACDF =BCEF =24 =12
DE=2×AB=6cm,DF=2×AC=5cm.
∴ Perimeter ofΔDEF=(DE+EF+DF)
=6+4+5=15cm.
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:
B
ABDE =ACDF =BCEF =24 =12
DE=2×AB=6cm,DF=2×AC=5cm.
∴ Perimeter ofΔDEF=(DE+EF+DF)
=6+4+5=15cm.
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