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In a triangle ABC, M is the mid-point of BC. If AMB = 45, and ACM = 30, then BAM is (B is not obtuse)
Options:
A .  30∘
B .  45∘
C .  < 30∘
D .  ≥ 45∘
Answer: Option D
:
D
Consider any triangle ABC, AM is a line connecting A to mid point of BC. Drop a perpendicular from A to BC touching BC at D. The angle ADM is a right angled triangle with 45 – 45 – 90 angles. Hence DAM = 45 and BAM > 45. BAM= 45If ABC =90. hence, answer is option (d)

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