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Question
In a totally irreversible isothermal expansion process for an ideal gas, ΔE = 0, ΔH = 0. Then ΔQ and ΔS will be
Options:
A .  ΔQ = 0, ΔS=0
B .  ΔQ = 0 , ΔS = +ve
C .  ΔQ = 0, ΔS = -ve
D .  ΔQ = +ve , ΔS= +ve
Answer: Option B

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