Question
If z = x+ iy is a complex number such that |z| = Re(iz)+1, then the locus of z is
Answer: Option D
:
D
z=x+iyiz=−y+ix
Given,|z|=Re(iz)+1⇒√x2+y2=−y+1⇒x2+y2=y2−2y+1⇒x2=1−2y
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:
D
z=x+iyiz=−y+ix
Given,|z|=Re(iz)+1⇒√x2+y2=−y+1⇒x2+y2=y2−2y+1⇒x2=1−2y
Was this answer helpful ?
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