Question
1−i1+i is equal to
Answer: Option B
:
B
1−i1+i=(1−i)(1−i)(1+i)(1−i)=1+(i)2−2i1+1=-i
Which can be written as cosπ2-isinπ2
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:
B
1−i1+i=(1−i)(1−i)(1+i)(1−i)=1+(i)2−2i1+1=-i
Which can be written as cosπ2-isinπ2
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