Question
If z is a complex number such that z2 = (¯z)2,then
Answer: Option C
:
C
Let z = x+iy, then its coonjucate ¯z = x-iy
Given that z2=(¯z)2
⇒ x2 -y2 + 2ixy =x2 -y2 - 2ixy⇒ 4ixy = 0
if x ≠ 0 then y = 0 and if y≠ 0 then x = 0
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:
C
Let z = x+iy, then its coonjucate ¯z = x-iy
Given that z2=(¯z)2
⇒ x2 -y2 + 2ixy =x2 -y2 - 2ixy⇒ 4ixy = 0
if x ≠ 0 then y = 0 and if y≠ 0 then x = 0
Was this answer helpful ?
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