Question
If y=√(1+cos 2 θ1−cos2 θ),dydθ at θ=3π4 is
Answer: Option B
:
B
y=√(1+cos2θ1−cos2θ)
=|cotθ|=−cotθ(θ=3π4)
∴dydθ=cosec2θ
dydθ|θ=3π/4=(√2)2=2
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:
B
y=√(1+cos2θ1−cos2θ)
=|cotθ|=−cotθ(θ=3π4)
∴dydθ=cosec2θ
dydθ|θ=3π/4=(√2)2=2
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