Question
The product of 2 consecutive natural numbers is 56. Solve this problem using completing the square method of quadratic equation. Write the equation obtained after completing the square and also write the smaller of the 2 numbers.
Answer: Option A
:
A
Let the smaller number bex. Then the larger numberwill be x+1.
Their product is x(x+1).
x(x+1)=56
x2+x−56=0
x2+x+(12)2–(12)2−56=0
(x+12)2−2254=0
x+12=152,−152
x=7,−8
The required number is 7 as -8 is not a natural number.
Was this answer helpful ?
:
A
Let the smaller number bex. Then the larger numberwill be x+1.
Their product is x(x+1).
x(x+1)=56
x2+x−56=0
x2+x+(12)2–(12)2−56=0
(x+12)2−2254=0
x+12=152,−152
x=7,−8
The required number is 7 as -8 is not a natural number.
Was this answer helpful ?
More Questions on This Topic :
Question 2. The nature of roots of x2−3x+2=0 will be:....
Question 7. Solve following equation for x:
x2−3x−10=0....
Latest Videos
Latest Test Papers
Submit Solution