Question
If x2+2ax+10−3a>0 for all x ∈ R, then
Answer: Option A
:
A
According to given condition,
4a2−4(10−3a)<0 ⇒ a2+3a−10<0
⇒ (a+5)(a−2)<0⇒−5<a<2.
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:
A
According to given condition,
4a2−4(10−3a)<0 ⇒ a2+3a−10<0
⇒ (a+5)(a−2)<0⇒−5<a<2.
Was this answer helpful ?
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