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If a=2^i+3^j+^k,b=2^i+p^j+3^k and c=2^i+17^j+3^k are coplanar vectors, then the value of p is  
Options:
A .  -4
B .  -1
C .  4
D .  -2
Answer: Option A
:
A
Since,a=2^i+3^j+^k,b=2^i+p^j+3^k and c=2^i+17^j+3^k are coplanar,
therefore [abc]=
2312p32173
=0p=4

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