Question
If the points A,B and C have position vectors (2,1,1), (6,-1,2) and (14,P) respectively and if they are collinear, then P =
Answer: Option B
:
B
⃗OA=2^i+^j+^k,⃗OB=6^i−^j+2^k,⃗OC=14^i−5^j+P^k⇒⃗AB=⃗OB−⃗OA=4^i−2^j+^k,⃗AC=⃗OC−⃗OA=12^i−6^j+(p−1)^k
A, B, C are collinear ⇒⃗AC=λ⃗AB⇒12^i−6^j+(p−1)^k=λ(4^i−2^j+^k)
⇒λ=3,p−1=3⇒p=4.
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:
B
⃗OA=2^i+^j+^k,⃗OB=6^i−^j+2^k,⃗OC=14^i−5^j+P^k⇒⃗AB=⃗OB−⃗OA=4^i−2^j+^k,⃗AC=⃗OC−⃗OA=12^i−6^j+(p−1)^k
A, B, C are collinear ⇒⃗AC=λ⃗AB⇒12^i−6^j+(p−1)^k=λ(4^i−2^j+^k)
⇒λ=3,p−1=3⇒p=4.
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