Question
If x, y, z and w be the digits of a number beginning from the left, the number is
Answer: Option D
Answer: (d)
In this problem, the digits of the number from the left are x, y, z and w respectively.So, x is at thousands places, y is at hundreds of places, z is at tens place and w is at ones place.Thus, the required number be= (1000×x) + (100×y) + (10×z) + (1×w)= (1000x + 100y + 10z + w)
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Answer: (d)
In this problem, the digits of the number from the left are x, y, z and w respectively.So, x is at thousands places, y is at hundreds of places, z is at tens place and w is at ones place.Thus, the required number be= (1000×x) + (100×y) + (10×z) + (1×w)= (1000x + 100y + 10z + w)
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