Question
If $$x + \frac{1}{x} = 2$$ then $${x^2} + \frac{1}{{{x^2}}}$$ is equal to?
Answer: Option B
$$\eqalign{
& x + \frac{1}{x} = 2{\text{ }} \cr
& {\text{But }}x = 1 \cr
& {\text{So, }}{x^2} + \frac{1}{{{x^2}}} = {1^2} + \frac{1}{{{1^2}}} = 2 \cr} $$
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$$\eqalign{
& x + \frac{1}{x} = 2{\text{ }} \cr
& {\text{But }}x = 1 \cr
& {\text{So, }}{x^2} + \frac{1}{{{x^2}}} = {1^2} + \frac{1}{{{1^2}}} = 2 \cr} $$
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