Question
If p3 - q3 = (p - q){(p -q)2 + xpq}, then the value of x is?
Answer: Option C
$$\eqalign{
& \Rightarrow {p^3} - {q^3} = \left( {p - q} \right)\left\{ {{{\left( {p - q} \right)}^2} + xpq} \right\} \cr
& \Rightarrow \left( {p - q} \right)\left\{ {{p^2} + {q^2} + pq} \right\} = \left( {p - q} \right)\left\{ {{p^2} + {q^2} - 2pq + xpq} \right\} \cr
& \Rightarrow {p^2} + {q^2} + pq = {p^2} + {q^2} - 2pq + xpq \cr
& \Rightarrow 3pq = xpq \cr
& \Rightarrow x = 3 \cr} $$
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$$\eqalign{
& \Rightarrow {p^3} - {q^3} = \left( {p - q} \right)\left\{ {{{\left( {p - q} \right)}^2} + xpq} \right\} \cr
& \Rightarrow \left( {p - q} \right)\left\{ {{p^2} + {q^2} + pq} \right\} = \left( {p - q} \right)\left\{ {{p^2} + {q^2} - 2pq + xpq} \right\} \cr
& \Rightarrow {p^2} + {q^2} + pq = {p^2} + {q^2} - 2pq + xpq \cr
& \Rightarrow 3pq = xpq \cr
& \Rightarrow x = 3 \cr} $$
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