If $${x^2} + {y^2} = 29$$ and xy = 10 where x > 0, y > 0, x > y, then the value of $$\frac{{x + y}}{{x - y}}$$ is? Options: A . &nbsp$$ - \frac{7}{3}$$ B . &nbsp$$\frac{7}{3}$$ C . &nbsp$$\frac{3}{7}$$ D . &nbsp$$ - \frac{3}{7}$$

If $${x^2} + {y^2} = 29$$ and xy = 10 where x > 0, y > 0, x

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If $${x^2} + {y^2} = 29$$ and xy = 10 where x > 0, y > 0, x > y, then the value of $$\frac{{x + y}}{{x - y}}$$ is?

Options:

A . $$ - \frac{7}{3}$$

B . $$\frac{7}{3}$$

C . $$\frac{3}{7}$$

D . $$ - \frac{3}{7}$$

Answer: Option B

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