Question
If $(x + 1/x)$= 2, then the value of $(x^99 +1/x^99-2)$ is :
Answer: Option A
Answer:(a)$x +1/x$= 2${x^2 +1}/x= 2$$x^2 + 1 = 2x$$x^2$ - 2x + 1 = 0$(x - 1)^2$ = 0x - 1 = 0x = 1$x^99 + 1/x^99 - 2$ = 1 + 1 - 2 = 0
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Answer:(a)$x +1/x$= 2${x^2 +1}/x= 2$$x^2 + 1 = 2x$$x^2$ - 2x + 1 = 0$(x - 1)^2$ = 0x - 1 = 0x = 1$x^99 + 1/x^99 - 2$ = 1 + 1 - 2 = 0
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