Question
If three objects of same mass are dropped from different heights h1, h2 & h3 such that h1 > h2 < h3, then which of the following is true about their corresponding potential energy (PE1, PE2 & PE3):
Answer: Option B
:
B
Potential Energy = Force × Displacement =mg×h where, m is the mass, g is acceleration due to gravity and h is the height.
Since the objects are of the same mass and acceleration due to gravity has a fixed value on earth, the force mg in all three cases aresame.
⇒Potential Energy =constant×h
⇒Potential energy is directly proportional to its height.
We know that,h1 > h2 < h3.
Therefore, PE1 > PE2 < PE3
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:
B
Potential Energy = Force × Displacement =mg×h where, m is the mass, g is acceleration due to gravity and h is the height.
Since the objects are of the same mass and acceleration due to gravity has a fixed value on earth, the force mg in all three cases aresame.
⇒Potential Energy =constant×h
⇒Potential energy is directly proportional to its height.
We know that,h1 > h2 < h3.
Therefore, PE1 > PE2 < PE3
Was this answer helpful ?
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