Question
If the third term in the binomial expansion of (1+x)m is -18x2, then the rational value of m is
Answer: Option B
:
B
mc2=−18⇒m(m−1)2=−18⇒4m2−4m+1=0⇒(2m−1)2=0⇒m=12
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:
B
mc2=−18⇒m(m−1)2=−18⇒4m2−4m+1=0⇒(2m−1)2=0⇒m=12
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