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Question
The first 3 terms in the expansion of (1+ax)n (n ≠ 0) are 1, 6x and 16x2. Then the value of a and n are respectively
Options:
A .  2 and 9
B .  3 and 2
C .  23 and 9
D .  32 and 6
Answer: Option C
:
C
nc1.ax=6x;nc2(ax)2=16x2an=6;n(n1)2a2=16a=23n=9

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