Question
If the measures of the sides of triangle are (x2 - 1), (x2 + 1) and 2x cm, then the triangle would be :
Answer: Option C
According to question,
Sides AB = x2 - 1
BC = 2x
AC = x2 + 1
By using Pythagoras theorem
AC2 = AB2 + BC2
(x2 + 1)2 = (x2 - 1)2 + (2x)2
x4 + 1 + 2x2 = x2 + 1 - 2x2 + 4x2
(x2 + 1)2 = (x2 + 1)2
∴ The triangle is right angle Δ
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According to question,
Sides AB = x2 - 1
BC = 2x
AC = x2 + 1
By using Pythagoras theorem
AC2 = AB2 + BC2
(x2 + 1)2 = (x2 - 1)2 + (2x)2
x4 + 1 + 2x2 = x2 + 1 - 2x2 + 4x2
(x2 + 1)2 = (x2 + 1)2
∴ The triangle is right angle Δ
Was this answer helpful ?
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