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Question


If the equation x2+2(k+2)x+9=0 has equal roots, then find the values of k.


Options:
A .   1, 4
B .   –1, 5
C .   1, –5
D .   –1, –4
Answer: Option C
:
C

Step 1:-  x2+2(k+2)x+9=0  a=1,b=2(k+2),c=9


                  D=4(k+2)24(9)=4(k2+4k5)       [D=b24ac ]


Step 2:- The roots of quadratic equation are real and equal only when D=0


                 4(k2+4k5)=0, k2+4k5=0


Step 3:-    k2+4k5=0


                   k2+5kk5=0


                    k(k+5)1(k+5)=0


                    (k1)(k+5)=0


                     k=1 or k=5



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