Question
If the critical angle for total internal reflection from a medium to vacuum is `30^circ` the velocity of light in the medium is
Answer: Option B
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From the relation , `mu = 1/sin C`
or ` c_v/c_m = 1/sinC`
where C = critical angle = `30^circ`
`c_v` = velocity of light in vacuum = 3 x `10^8` m/s
`c_m` = velocity of light in medium
Therefore , `(3 xx 10^8)/(c_m) = (1)/(sin30^circ)`
or `c_m= 1/2 xx 3 xx 10^8`
= 1.5 x` 10^8` m/s
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