Question
80 g of water at `30^circ C` is poured on a large block of ice at `0^circ C` .The mass of the ice that melts is :
Answer: Option D
Was this answer helpful ?
By the principle of calorimety Heat lost = heat gain
`Ms Delta theta `= mL
where : m = mass of ice
M = mass of water = 80g
s = specific heat of water = 1 cal/`g^circ C`
`Delta theta` = temperature of water = `30^circ`
L = latent heat of ice = 80 cal/g
So, 80 x 1 x`30^circ` = m x 80
Hence , m = 30 g.
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution