Question
Find the change in internal energy of the system when a system absorbs 2 kcal of heat and at the same time does 500 J of work :
Answer: Option A
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According to the first law of thermodynamics
`Delta Q = Delta W + Delta u`
Given : `Delta Q = 2 xx 10^3 xx 4.2 J`
`Delta W = 500 J`
So, ` Delta u = 2 xx 10^3 xx 4.2 J - 500 J`
` = 8400 - 500 = 7900 J`
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