If for all real values of x , 4 x 2 + 1 64 x 2 − 96 x s i n α + 5 < 1 32 , then α lies in the interval. Options: A . &nbsp(0,π3) B . &nbsp(π3,2π3) C . &nbsp(2π3,π) D . &nbsp(4π3,5π3)

If for all real values of x,4x2+164x2−96 x sin α+5&l

Question

If for all real values of

x, \frac{4 x^{2} + 1}{64 x^{2} - 96 x s i n α + 5} < \frac{1}{32}

, then

α

lies in the interval.

Options:

A . (0,π3)

B . (π3,2π3)

C . (2π3,π)

D . (4π3,5π3)

Answer: Option D
:
D
Option D is the correct answer.

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