If θ is an acute angle and s i n θ = p − 6 8 − p , then p must satisfy Options: A . &nbsp6≤p B . &nbsp6≤p C . &nbsp3≤p≤4 D . &nbsp4≤p

Answer: Option B : B (b) θ is an acute angle so 0 ∘ ≤ θ < 90 ∘ ∴ 0 ≤ p − 6 8 − p < 1 => 0 ≤ ( p − 6 ) < ( 8 − p ) = > 6 ≤ p < 7 .

If θ is an acute angle and sin θ=p−68−p, then p m

Question

θ

is an acute angle and

s i n θ = \frac{p - 6}{8 - p},

then p must satisfy

Options:

A . 6≤p

B . 6≤p

C . 3≤p≤4

D . 4≤p

Answer: Option B
:
B
(b)

θ

is an acute angle so

0^{\circ} \leq θ < 90^{\circ}

∴ 0 \leq \frac{p - 6}{8 - p} < 1

0 \leq (p - 6) < (8 - p) => 6 \leq p < 7

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