Question
If f(x) = {sinxx≠nπ,n=0,±1,±2...2,otherwise and g(x) = ⎧⎪⎨⎪⎩x2+1,x≠0,24,x=05,x=2, then limx→0g{f(x)} is
Answer: Option D
:
D
Given that,
f(x) = {sinxx≠nπ,n=0,±1,±2...2,otherwise
and
g(x) = ⎧⎪⎨⎪⎩x2+1,x≠0,24,x=05,x=2
Then limx→0g[f(x)]=limx→9g(sinx)
=limx→0(sin2x+1)=1
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:
D
Given that,
f(x) = {sinxx≠nπ,n=0,±1,±2...2,otherwise
and
g(x) = ⎧⎪⎨⎪⎩x2+1,x≠0,24,x=05,x=2
Then limx→0g[f(x)]=limx→9g(sinx)
=limx→0(sin2x+1)=1
Was this answer helpful ?
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