If Avogadro's number is 6×1023 then the number of protons, neutrons an

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If Avogadro's number is

6 \times 10^{23}

then the number of protons, neutrons and electrons in 14 g of

_{6} C^{14}

are respectively

Options:

A . 36×1023,48×1023,36×1023

B . 36×1023,36×1023,36×1021

C . 48×1023,36×1023,48×1021

D . 48×1023,48×1023,36×1021

Answer: Option A
:
A
Since the number of protons, neutrons and electrons in an atom of

_{6} C^{14}

are 6, 8 and 6 respectively. As 14 gm of

_{6} C^{14}

contains

6 \times 10^{23}

atoms, therefore the numbers of protons, neutrons and electrons in 14 gm of

_{6} C^{14}

are

6 \times 6 \times 10^{23}, = 36 \times 10^{23}, 8 \times 6 \times 10^{23} = 48 \times 10^{23}, 6 \times 6 \times 10^{23} = 36 \times 10^{23}

.

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