Question
If a = 23×3, b = 2×3×5, c = 3n×5 and LCM (a, b, c) = 23×32×5, then n = ?
(Here, n is a natural number)
Answer: Option B
:
B
Given: a = 23×3
b = 2×3×5
c = 3n×5
LCM (a, b, c) = 23×32×5 ... (1)
Since, to find LCM we need to take the prime factors with their highest degree:
LCM will be 23×3n×5 ... (2) (n≥1)
On comparing we get,
n = 2
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:
B
Given: a = 23×3
b = 2×3×5
c = 3n×5
LCM (a, b, c) = 23×32×5 ... (1)
Since, to find LCM we need to take the prime factors with their highest degree:
LCM will be 23×3n×5 ... (2) (n≥1)
On comparing we get,
n = 2
Was this answer helpful ?
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