Question
If ` 2^x = 3^y = 6^-z, then (1/x + 1/y + 1/z)` is equal to :
Answer: Option A
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Let `2^x = 3^y = 6^-z = k` `hArr 2 =k ^(1/x) , 3 = k^(1/y) and 6 = K^-(1/z)`
Now 2 x 3 = `hArr k^(1/x) xx k^(1/y) = k^-(1/z) hArr k^(1/x+1/y) = k^-(1/z)`
`:.` `1/x + 1/y = - 1/z hArr 1/x + 1/y + 1/z = `o.
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