If ( 1 2 + 2 2 + 3 2 + … + x 2 ) = \(\frac{x ( x + 1 ) ( 2x + 1 ) }{6}\) , then ( 1 2 + 3 2 + 5 2 + … + 19 2 ) = ? Options: A . &nbsp1320 B . &nbsp1330 C . &nbsp1340 D . &nbsp1350

If ( 12 + 22 + 32 + … + x2 ) = \(\frac{x ( x + 1 ) ( 2x + 1 ) }{6}\

Question

If ( 1² + 2² + 3² + … + x² ) = \(\frac{x ( x + 1 ) ( 2x + 1 ) }{6}\) , then ( 1² + 3² + 5² + … + 19² ) = ?

Options:

A . 1320

B . 1330

C . 1340

D . 1350

Answer: Option B

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