Question
How many 3-digit number can be formed from the digits 2, 3, 5, 6, 7 and 9 , which are divisible by 5 and none of the digits is repeated ?
Answer: Option D
Was this answer helpful ?
Since each desired number is divisible by 5, so we must have 5 at the unit place , so here is 1 way of doing it .
Tens place can be filled by any of the remaining 5 numbers.
So, there are 5 ways of filling the tens place.
The hundreds place can now be filled by any of the remaining 4 digits . so there are 4 ways of filling it .
`:.` Required number of numbers = (1 x 5 x 4) = 20.
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution