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Question


Harikiran purchased a house in Rs. 15000 and paid Rs. 5000 at once. Rest money he promised to pay in annual instalment of Rs. 1000 with 10% per annum interest. How much money is to be paid by him


Options:
A .   Rs. 21555 
B .   Rs. 20475
C .   Rs. 20500
D .   Rs. 20700
Answer: Option C
:
C

It will take 10 years for harikiran to pay off Rs. 10000 in 10 yearly


installments.


∵ He pays 10% annual interest on interest on remaining amount


∴ Money given in first year


= 1000 +  10000×10100 = Rs. 2000


Money given in second year = 1000 + interest of (10000 - 1000) with interest rate 10% per annum


= 1000 +  9000×10100 = Rs. 1900


Money paid  in third year = Rs. 1800 etc.


So money given by Jairam in 10 years will be Rs. 2000, Rs.1900, Rs. 1800, Rs. 1700,......,


which is in arithmetic progression,


whose first term a = 2000 and d = -100


Total money given in 10 years = sum of 10 terms of arithmetic 


progression


102[2(2000) + (10 - 1)(-100)] = Rs. 15500


Therefore, total money given by harikiran 


= 5000 + 15500 = Rs. 20500.



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