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Given that a> 0 and i belongs to a set of natural numbers. If a1,a2,a3.....a2n are in AP, then find the value of a1+a2na1+a2+a2+a2n1a2+a3............+an+an+1an+an+1
Options:
A .  n-1         
B .  na1+a2n√a1+√an+1
C .  n−1√a1+√an+1
D .  n+1√a1+√an+1
E .  3q+ r
Answer: Option B
:
B
Let the AP be 1,2,3,4,5
At n=1, the AP = 1,2
a1=1 and a2=2
The value of the expression =32.4

Only option (b) gives this value

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