Question
From a point P on a level ground, the angle of elevation of the top of a tower is 30°. If the tower is 100 m high, the distance of point P from the foot of the tower is :_________?
Answer: Option C
LET AB BE THE TOWER. THEN, ∠APB = 30° AND AB = 100 M, AB/AP = TAN 30° = 1/√3 AP = (AB X √3)= 100√3 M. = (100 X 1.73) M = 173 M.
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LET AB BE THE TOWER. THEN, ∠APB = 30° AND AB = 100 M, AB/AP = TAN 30° = 1/√3 AP = (AB X √3)= 100√3 M. = (100 X 1.73) M = 173 M.
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